27=(3k)(3k)(3k)

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Solution for 27=(3k)(3k)(3k) equation: 



27=(3k)(3k)(3k)

We move all terms to the left:

27-((3k)(3k)(3k))=0

determiningTheFunctionDomain
-3k3k3k+27=0

We move all terms containing k to the left, all other terms to the right

-3k3k3k=-27

k=-27/1

k=-27

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