276=-16t2+20t+300

Solution for 276=-16t2+20t+300 equation:

276=-16t^2+20t+300

We move all terms to the left:

276-(-16t^2+20t+300)=0

We get rid of parentheses

16t^2-20t-300+276=0

We add all the numbers together, and all the variables

16t^2-20t-24=0

a = 16; b = -20; c = -24;
Δ = b2-4ac
Δ = -202-4·16·(-24)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-44}{2*16}=\frac{-24}{32}
=-3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+44}{2*16}=\frac{64}{32}
=2
$