9(2-3x)-29=8x-(x+23)

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Solution for 9(2-3x)-29=8x-(x+23) equation: 



9(2-3x)-29=8x-(x+23)

We move all terms to the left:

9(2-3x)-29-(8x-(x+23))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-(x+23))-29=0

We multiply parentheses

-27x-(8x-(x+23))+18-29=0



We calculate terms in parentheses: -(8x-(x+23)), so:

8x-(x+23)

We get rid of parentheses

8x-x-23

We add all the numbers together, and all the variables

7x-23

Back to the equation:

-(7x-23)



We add all the numbers together, and all the variables

-27x-(7x-23)-11=0

We get rid of parentheses

-27x-7x+23-11=0

We add all the numbers together, and all the variables

-34x+12=0

We move all terms containing x to the left, all other terms to the right

-34x=-12

x=-12/-34

x=6/17

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