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270=(x)(x+3)
We move all terms to the left:
270-((x)(x+3))=0
We calculate terms in parentheses: -(x(x+3)), so:We get rid of parentheses
x(x+3)
We multiply parentheses
x^2+3x
Back to the equation:
-(x^2+3x)
-x^2-3x+270=0
We add all the numbers together, and all the variables
-1x^2-3x+270=0
a = -1; b = -3; c = +270;
Δ = b2-4ac
Δ = -32-4·(-1)·270
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-33}{2*-1}=\frac{-30}{-2} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+33}{2*-1}=\frac{36}{-2} =-18 $
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