(x/20)+9x/35)=1

Solution for (x/20)+9x/35)=1 equation:

(x/20)+9x/35)=1

We move all terms to the left:

(x/20)+9x/35)-(1)=0

We add all the numbers together, and all the variables

(+x/20)+9x/35)-1=0

We get rid of parentheses

x/20+9x/35)-1=0

We calculate fractions


35x^2/()+180x/()=0

We multiply all the terms by the denominator


35x^2+180x=0

a = 35; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·35·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*35}=\frac{-360}{70}
=-5+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*35}=\frac{0}{70}
=0
$