27(p-1)=6(p-8)-12

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Solution for 27(p-1)=6(p-8)-12 equation: 



27(p-1)=6(p-8)-12

We move all terms to the left:

27(p-1)-(6(p-8)-12)=0

We multiply parentheses

27p-(6(p-8)-12)-27=0



We calculate terms in parentheses: -(6(p-8)-12), so:

6(p-8)-12

We multiply parentheses

6p-48-12

We add all the numbers together, and all the variables

6p-60

Back to the equation:

-(6p-60)



We get rid of parentheses

27p-6p+60-27=0

We add all the numbers together, and all the variables

21p+33=0

We move all terms containing p to the left, all other terms to the right

21p=-33

p=-33/21

p=-1+4/7

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