If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((38/10)/(4c+3))=2/(40/19)
We move all terms to the left:
((38/10)/(4c+3))-(2/(40/19))=0
We can not solve this equation
| 13-v=12 | | 12+3m=7m+16 | | 3.13(z-5)+-7.28=2.11 | | (2y-5)=85 | | 2x-4(x-5)=-4+3x-1 | | -0.19(w-5)=-0.76 | | a8-6=-8 | | -6x+3(x+2)=3 | | 3x−8=4x−8 | | p+57=66 | | 8x-42+4x=180 | | 8-4s=-10s-4 | | -9p-9=18 | | p+-7=4 | | 4(x+2)=8x+36 | | -12=-7+2y | | -2x=-14=-2 | | 8x-42=4x | | 19-v=1 | | 4x2−10=134 | | 2(p-4.7)-9=-2.2 | | 27(p-1)=6(p-1)-12 | | x×x+17=x(x-11)-49 | | 9b-5=-41 | | 14x+7x+6=5x-20 | | n=3(n-1) | | 17-9a=6 | | 10=8+x/3 | | b+16=38 | | (90−x)+2x+x=18090−4x=1804x=270x=67.5 | | 6/y=15/30 | | Y=|4x+16| |