26c-(2c+3)=2(c+4)+c

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Solution for 26c-(2c+3)=2(c+4)+c equation: 



26c-(2c+3)=2(c+4)+c

We move all terms to the left:

26c-(2c+3)-(2(c+4)+c)=0

We get rid of parentheses

26c-2c-(2(c+4)+c)-3=0



We calculate terms in parentheses: -(2(c+4)+c), so:

2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We add all the numbers together, and all the variables

24c-(3c+8)-3=0

We get rid of parentheses

24c-3c-8-3=0

We add all the numbers together, and all the variables

21c-11=0

We move all terms containing c to the left, all other terms to the right

21c=11

c=11/21

c=11/21

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