(1/3)n-4=-(1/3)n+18

Solution for (1/3)n-4=-(1/3)n+18 equation:

(1/3)n-4=-(1/3)n+18

We move all terms to the left:

(1/3)n-4-(-(1/3)n+18)=0


Domain of the equation: 3)n!=0

n!=0/1

n!=0

n∈R



Domain of the equation: 3)n+18)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

(+1/3)n-(-(+1/3)n+18)-4=0

We multiply parentheses

n^2-(-(+1/3)n+18)-4=0

We multiply all the terms by the denominator


n^2*3)n+18)-(-(-4*3)n+18)+1=0

We add all the numbers together, and all the variables

n^2*3)n+18)-(-(-12)n+18)+1=0

Wy multiply elements

3n^3-12)n+18)+1=0

We do not support enpression: n^3