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26=6x(4x-1)
We move all terms to the left:
26-(6x(4x-1))=0
We calculate terms in parentheses: -(6x(4x-1)), so:We get rid of parentheses
6x(4x-1)
We multiply parentheses
24x^2-6x
Back to the equation:
-(24x^2-6x)
-24x^2+6x+26=0
a = -24; b = 6; c = +26;
Δ = b2-4ac
Δ = 62-4·(-24)·26
Δ = 2532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2532}=\sqrt{4*633}=\sqrt{4}*\sqrt{633}=2\sqrt{633}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{633}}{2*-24}=\frac{-6-2\sqrt{633}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{633}}{2*-24}=\frac{-6+2\sqrt{633}}{-48} $
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