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26-2(2x+2)=2(x+2)+3x
We move all terms to the left:
26-2(2x+2)-(2(x+2)+3x)=0
We multiply parentheses
-4x-(2(x+2)+3x)-4+26=0
We calculate terms in parentheses: -(2(x+2)+3x), so:We add all the numbers together, and all the variables
2(x+2)+3x
We add all the numbers together, and all the variables
3x+2(x+2)
We multiply parentheses
3x+2x+4
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
-4x-(5x+4)+22=0
We get rid of parentheses
-4x-5x-4+22=0
We add all the numbers together, and all the variables
-9x+18=0
We move all terms containing x to the left, all other terms to the right
-9x=-18
x=-18/-9
x=+2
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