3n-20=2(n-6)

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Solution for 3n-20=2(n-6) equation: 



3n-20=2(n-6)

We move all terms to the left:

3n-20-(2(n-6))=0



We calculate terms in parentheses: -(2(n-6)), so:

2(n-6)

We multiply parentheses

2n-12

Back to the equation:

-(2n-12)



We get rid of parentheses

3n-2n+12-20=0

We add all the numbers together, and all the variables

n-8=0

We move all terms containing n to the left, all other terms to the right

n=8

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