26+x=((x+23)+(12)-14+x)

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Solution for 26+x=((x+23)+(12)-14+x) equation:



26+x=((x+23)+(12)-14+x)
We move all terms to the left:
26+x-(((x+23)+(12)-14+x))=0
We calculate terms in parentheses: -(((x+23)+12-14+x)), so:
((x+23)+12-14+x)
We calculate terms in parentheses: +((x+23)+12-14+x), so:
(x+23)+12-14+x
determiningTheFunctionDomain (x+23)+x+12-14
We add all the numbers together, and all the variables
x+(x+23)-2
We get rid of parentheses
x+x+23-2
We add all the numbers together, and all the variables
2x+21
Back to the equation:
+(2x+21)
We get rid of parentheses
2x+21
Back to the equation:
-(2x+21)
We get rid of parentheses
x-2x-21+26=0
We add all the numbers together, and all the variables
-1x+5=0
We move all terms containing x to the left, all other terms to the right
-x=-5
x=-5/-1
x=+5

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