3x-1=(2x-4)+(2x-3)-2

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Solution for 3x-1=(2x-4)+(2x-3)-2 equation: 



3x-1=(2x-4)+(2x-3)-2

We move all terms to the left:

3x-1-((2x-4)+(2x-3)-2)=0



We calculate terms in parentheses: -((2x-4)+(2x-3)-2), so:

(2x-4)+(2x-3)-2

We get rid of parentheses

2x+2x-4-3-2

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We get rid of parentheses

3x-4x+9-1=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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