26(3-b)=-13(b-1)

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Solution for 26(3-b)=-13(b-1) equation: 



26(3-b)=-13(b-1)

We move all terms to the left:

26(3-b)-(-13(b-1))=0

We add all the numbers together, and all the variables

26(-1b+3)-(-13(b-1))=0

We multiply parentheses

-26b-(-13(b-1))+78=0



We calculate terms in parentheses: -(-13(b-1)), so:

-13(b-1)

We multiply parentheses

-13b+13

Back to the equation:

-(-13b+13)



We get rid of parentheses

-26b+13b-13+78=0

We add all the numbers together, and all the variables

-13b+65=0

We move all terms containing b to the left, all other terms to the right

-13b=-65

b=-65/-13

b=+5

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