26(3-b)=-14(b-1)

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Solution for 26(3-b)=-14(b-1) equation: 



26(3-b)=-14(b-1)

We move all terms to the left:

26(3-b)-(-14(b-1))=0

We add all the numbers together, and all the variables

26(-1b+3)-(-14(b-1))=0

We multiply parentheses

-26b-(-14(b-1))+78=0



We calculate terms in parentheses: -(-14(b-1)), so:

-14(b-1)

We multiply parentheses

-14b+14

Back to the equation:

-(-14b+14)



We get rid of parentheses

-26b+14b-14+78=0

We add all the numbers together, and all the variables

-12b+64=0

We move all terms containing b to the left, all other terms to the right

-12b=-64

b=-64/-12

b=5+1/3

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