25x2-8x-17=0

Solution for 25x2-8x-17=0 equation:

25x^2-8x-17=0

a = 25; b = -8; c = -17;
Δ = b2-4ac
Δ = -82-4·25·(-17)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-42}{2*25}=\frac{-34}{50}
=-17/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+42}{2*25}=\frac{50}{50}
=1
$