1/2(24+2v)=5v-33

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Solution for 1/2(24+2v)=5v-33 equation: 



1/2(24+2v)=5v-33

We move all terms to the left:

1/2(24+2v)-(5v-33)=0



Domain of the equation: 2(24+2v)!=0

v∈R



We add all the numbers together, and all the variables

1/2(2v+24)-(5v-33)=0

We get rid of parentheses

1/2(2v+24)-5v+33=0

We multiply all the terms by the denominator


-5v*2(2v+24)+33*2(2v+24)+1=0

Wy multiply elements

-10v^2(2+66v(2+1=0

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