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25x^2+60x=-36
We move all terms to the left:
25x^2+60x-(-36)=0
We add all the numbers together, and all the variables
25x^2+60x+36=0
a = 25; b = 60; c = +36;
Δ = b2-4ac
Δ = 602-4·25·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-60}{50}=-1+1/5$
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