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25x+11=-6x^2
We move all terms to the left:
25x+11-(-6x^2)=0
We get rid of parentheses
6x^2+25x+11=0
a = 6; b = 25; c = +11;
Δ = b2-4ac
Δ = 252-4·6·11
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-19}{2*6}=\frac{-44}{12} =-3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+19}{2*6}=\frac{-6}{12} =-1/2 $
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