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25x(x-25)=-4
We move all terms to the left:
25x(x-25)-(-4)=0
We add all the numbers together, and all the variables
25x(x-25)+4=0
We multiply parentheses
25x^2-625x+4=0
a = 25; b = -625; c = +4;
Δ = b2-4ac
Δ = -6252-4·25·4
Δ = 390225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{390225}=\sqrt{3025*129}=\sqrt{3025}*\sqrt{129}=55\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-625)-55\sqrt{129}}{2*25}=\frac{625-55\sqrt{129}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-625)+55\sqrt{129}}{2*25}=\frac{625+55\sqrt{129}}{50} $
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