2x+2(2x-4)=58

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Solution for 2x+2(2x-4)=58 equation: 



2x+2(2x-4)=58

We move all terms to the left:

2x+2(2x-4)-(58)=0

We multiply parentheses

2x+4x-8-58=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11

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