25=(b2*3)/3

Solution for 25=(b2*3)/3 equation:

25=(b2*3)/3

We move all terms to the left:

25-((b2*3)/3)=0

We add all the numbers together, and all the variables

-((+b2*3)/3)+25=0

We multiply all the terms by the denominator


-((+b2*3)+25*3)=0


We calculate terms in parentheses: -((+b2*3)+25*3), so:

(+b2*3)+25*3

We add all the numbers together, and all the variables

(+b2*3)+75

We get rid of parentheses

b2*3+75

Wy multiply elements

3b^2+75

Back to the equation:

-(3b^2+75)


We get rid of parentheses

-3b^2-75=0

a = -3; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·(-3)·(-75)
Δ = -900
Delta is less than zero, so there is no solution for the equation