25-5+7y-3(y+5)=-2(4y-3)-9(y-1)-10y+4

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Solution for 25-5+7y-3(y+5)=-2(4y-3)-9(y-1)-10y+4 equation: 



25-5+7y-3(y+5)=-2(4y-3)-9(y-1)-10y+4

We move all terms to the left:

25-5+7y-3(y+5)-(-2(4y-3)-9(y-1)-10y+4)=0

We add all the numbers together, and all the variables

7y-3(y+5)-(-2(4y-3)-9(y-1)-10y+4)+20=0

We multiply parentheses

7y-3y-(-2(4y-3)-9(y-1)-10y+4)-15+20=0



We calculate terms in parentheses: -(-2(4y-3)-9(y-1)-10y+4), so:

-2(4y-3)-9(y-1)-10y+4

We add all the numbers together, and all the variables

-10y-2(4y-3)-9(y-1)+4

We multiply parentheses

-10y-8y-9y+6+9+4

We add all the numbers together, and all the variables

-27y+19

Back to the equation:

-(-27y+19)



We add all the numbers together, and all the variables

4y-(-27y+19)+5=0

We get rid of parentheses

4y+27y-19+5=0

We add all the numbers together, and all the variables

31y-14=0

We move all terms containing y to the left, all other terms to the right

31y=14

y=14/31

y=14/31

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