(3)/(4)w-(1)/(2)w-4=12

Solution for (3)/(4)w-(1)/(2)w-4=12 equation:

(3)/(4)w-(1)/(2)w-4=12

We move all terms to the left:

(3)/(4)w-(1)/(2)w-4-(12)=0


Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R



Domain of the equation: 2w!=0

w!=0/2

w!=0

w∈R


We add all the numbers together, and all the variables

3/4w-1/2w-16=0

We calculate fractions


6w/8w^2+(-4w)/8w^2-16=0

We multiply all the terms by the denominator


6w+(-4w)-16*8w^2=0

Wy multiply elements

-128w^2+6w+(-4w)=0

We get rid of parentheses

-128w^2+6w-4w=0

We add all the numbers together, and all the variables

-128w^2+2w=0

a = -128; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-128)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-128}=\frac{-4}{-256}
=1/64
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-128}=\frac{0}{-256}
=0
$