25+q=(1/2)q-3

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Solution for 25+q=(1/2)q-3 equation: 



25+q=(1/2)q-3

We move all terms to the left:

25+q-((1/2)q-3)=0



Domain of the equation: 2)q-3)!=0

q!=0/1

q!=0

q∈R



We add all the numbers together, and all the variables

q-((+1/2)q-3)+25=0

We multiply all the terms by the denominator


q*2)q-3)-((+25*2)q-3)+1=0

We add all the numbers together, and all the variables

q*2)q-3)-(50q-3)+1=0

Wy multiply elements

2q^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{0}{4}=0$

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