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x=2/3x-24
We move all terms to the left:
x-(2/3x-24)=0
Domain of the equation: 3x-24)!=0We get rid of parentheses
x∈R
x-2/3x+24=0
We multiply all the terms by the denominator
x*3x+24*3x-2=0
Wy multiply elements
3x^2+72x-2=0
a = 3; b = 72; c = -2;
Δ = b2-4ac
Δ = 722-4·3·(-2)
Δ = 5208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5208}=\sqrt{4*1302}=\sqrt{4}*\sqrt{1302}=2\sqrt{1302}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-2\sqrt{1302}}{2*3}=\frac{-72-2\sqrt{1302}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+2\sqrt{1302}}{2*3}=\frac{-72+2\sqrt{1302}}{6} $
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