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240=9/5(k-273.15)+32
We move all terms to the left:
240-(9/5(k-273.15)+32)=0
Domain of the equation: 5(k-273.15)+32)!=0We multiply all the terms by the denominator
k∈R
-(9+240*5(k-273.15)+32)=0
We calculate terms in parentheses: -(9+240*5(k-273.15)+32), so:
9+240*5(k-273.15)+32
determiningTheFunctionDomain 240*5(k-273.15)+9+32
We add all the numbers together, and all the variables
240*5(k-273.15)+41
Wy multiply elements
1200k(k+41
Back to the equation:
-(1200k(k+41)
We calculate terms in parentheses: -(1200k(k+41), so:
1200k(k+41
We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
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We calculate terms in parentheses: -(1200k(k+41), so:
1200k(k+41
We calculate terms in parentheses: -(1200k(k+41), so:
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