12=(3/4)x+12

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Solution for 12=(3/4)x+12 equation: 



12=(3/4)x+12

We move all terms to the left:

12-((3/4)x+12)=0



Domain of the equation: 4)x+12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3/4)x+12)+12=0

We multiply all the terms by the denominator


-((+3+12*4)x+12)=0



We calculate terms in parentheses: -((+3+12*4)x+12), so:

(+3+12*4)x+12

We add all the numbers together, and all the variables

51x+12

Back to the equation:

-(51x+12)



We get rid of parentheses

-51x-12=0

We move all terms containing x to the left, all other terms to the right

-51x=12

x=12/-51

x=-4/17

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