240(r-5)=160(r+5)

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Solution for 240(r-5)=160(r+5) equation: 



240(r-5)=160(r+5)

We move all terms to the left:

240(r-5)-(160(r+5))=0

We multiply parentheses

240r-(160(r+5))-1200=0



We calculate terms in parentheses: -(160(r+5)), so:

160(r+5)

We multiply parentheses

160r+800

Back to the equation:

-(160r+800)



We get rid of parentheses

240r-160r-800-1200=0

We add all the numbers together, and all the variables

80r-2000=0

We move all terms containing r to the left, all other terms to the right

80r=2000

r=2000/80

r=25

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