24+4(2+4z)=64

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Solution for 24+4(2+4z)=64 equation: 



24+4(2+4z)=64

We move all terms to the left:

24+4(2+4z)-(64)=0

We add all the numbers together, and all the variables

4(4z+2)+24-64=0

We add all the numbers together, and all the variables

4(4z+2)-40=0

We multiply parentheses

16z+8-40=0

We add all the numbers together, and all the variables

16z-32=0

We move all terms containing z to the left, all other terms to the right

16z=32

z=32/16

z=2

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