2(y+1)+7=(y-2)+2y

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Solution for 2(y+1)+7=(y-2)+2y equation: 



2(y+1)+7=(y-2)+2y

We move all terms to the left:

2(y+1)+7-((y-2)+2y)=0

We multiply parentheses

2y-((y-2)+2y)+2+7=0



We calculate terms in parentheses: -((y-2)+2y), so:

(y-2)+2y

We add all the numbers together, and all the variables

2y+(y-2)

We get rid of parentheses

2y+y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We add all the numbers together, and all the variables

2y-(3y-2)+9=0

We get rid of parentheses

2y-3y+2+9=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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