23x-41=7(x+3)+2

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Solution for 23x-41=7(x+3)+2 equation: 



23x-41=7(x+3)+2

We move all terms to the left:

23x-41-(7(x+3)+2)=0



We calculate terms in parentheses: -(7(x+3)+2), so:

7(x+3)+2

We multiply parentheses

7x+21+2

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We get rid of parentheses

23x-7x-23-41=0

We add all the numbers together, and all the variables

16x-64=0

We move all terms containing x to the left, all other terms to the right

16x=64

x=64/16

x=4

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