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7/9x+2=5x-13
We move all terms to the left:
7/9x+2-(5x-13)=0
Domain of the equation: 9x!=0We get rid of parentheses
x!=0/9
x!=0
x∈R
7/9x-5x+13+2=0
We multiply all the terms by the denominator
-5x*9x+13*9x+2*9x+7=0
Wy multiply elements
-45x^2+117x+18x+7=0
We add all the numbers together, and all the variables
-45x^2+135x+7=0
a = -45; b = 135; c = +7;
Δ = b2-4ac
Δ = 1352-4·(-45)·7
Δ = 19485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19485}=\sqrt{9*2165}=\sqrt{9}*\sqrt{2165}=3\sqrt{2165}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135)-3\sqrt{2165}}{2*-45}=\frac{-135-3\sqrt{2165}}{-90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135)+3\sqrt{2165}}{2*-45}=\frac{-135+3\sqrt{2165}}{-90} $
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