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23x-12-11x=4(3x-4)+4
We move all terms to the left:
23x-12-11x-(4(3x-4)+4)=0
We add all the numbers together, and all the variables
12x-(4(3x-4)+4)-12=0
We calculate terms in parentheses: -(4(3x-4)+4), so:We get rid of parentheses
4(3x-4)+4
We multiply parentheses
12x-16+4
We add all the numbers together, and all the variables
12x-12
Back to the equation:
-(12x-12)
12x-12x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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