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23x(3x-270)=0
We multiply parentheses
69x^2-6210x=0
a = 69; b = -6210; c = 0;
Δ = b2-4ac
Δ = -62102-4·69·0
Δ = 38564100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38564100}=6210$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6210)-6210}{2*69}=\frac{0}{138} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6210)+6210}{2*69}=\frac{12420}{138} =90 $
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