(X+4+x-2)2=x+3+x+5+x+4

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Solution for (X+4+x-2)2=x+3+x+5+x+4 equation: 



(X+4+X-2)2=X+3+X+5+X+4

We move all terms to the left:

(X+4+X-2)2-(X+3+X+5+X+4)=0

We add all the numbers together, and all the variables

(2X+2)2-(3X+12)=0

We multiply parentheses

4X-(3X+12)+4=0

We get rid of parentheses

4X-3X-12+4=0

We add all the numbers together, and all the variables

X-8=0

We move all terms containing X to the left, all other terms to the right

X=8

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