23c-3(6-2c)=27

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Solution for 23c-3(6-2c)=27 equation: 



23c-3(6-2c)=27

We move all terms to the left:

23c-3(6-2c)-(27)=0

We add all the numbers together, and all the variables

23c-3(-2c+6)-27=0

We multiply parentheses

23c+6c-18-27=0

We add all the numbers together, and all the variables

29c-45=0

We move all terms containing c to the left, all other terms to the right

29c=45

c=45/29

c=1+16/29

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