6-4(3-2x)=5(x-4)-10

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Solution for 6-4(3-2x)=5(x-4)-10 equation: 



6-4(3-2x)=5(x-4)-10

We move all terms to the left:

6-4(3-2x)-(5(x-4)-10)=0

We add all the numbers together, and all the variables

-4(-2x+3)-(5(x-4)-10)+6=0

We multiply parentheses

8x-(5(x-4)-10)-12+6=0



We calculate terms in parentheses: -(5(x-4)-10), so:

5(x-4)-10

We multiply parentheses

5x-20-10

We add all the numbers together, and all the variables

5x-30

Back to the equation:

-(5x-30)



We add all the numbers together, and all the variables

8x-(5x-30)-6=0

We get rid of parentheses

8x-5x+30-6=0

We add all the numbers together, and all the variables

3x+24=0

We move all terms containing x to the left, all other terms to the right

3x=-24

x=-24/3

x=-8

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