23-5n=2(n-2)+2n

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Solution for 23-5n=2(n-2)+2n equation: 



23-5n=2(n-2)+2n

We move all terms to the left:

23-5n-(2(n-2)+2n)=0



We calculate terms in parentheses: -(2(n-2)+2n), so:

2(n-2)+2n

We add all the numbers together, and all the variables

2n+2(n-2)

We multiply parentheses

2n+2n-4

We add all the numbers together, and all the variables

4n-4

Back to the equation:

-(4n-4)



We get rid of parentheses

-5n-4n+4+23=0

We add all the numbers together, and all the variables

-9n+27=0

We move all terms containing n to the left, all other terms to the right

-9n=-27

n=-27/-9

n=+3

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