b-3=2(1-5b)-5

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Solution for b-3=2(1-5b)-5 equation: 



b-3=2(1-5b)-5

We move all terms to the left:

b-3-(2(1-5b)-5)=0

We add all the numbers together, and all the variables

b-(2(-5b+1)-5)-3=0



We calculate terms in parentheses: -(2(-5b+1)-5), so:

2(-5b+1)-5

We multiply parentheses

-10b+2-5

We add all the numbers together, and all the variables

-10b-3

Back to the equation:

-(-10b-3)



We get rid of parentheses

b+10b+3-3=0

We add all the numbers together, and all the variables

11b=0

b=0/11

b=0

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