23-5k=2(2k-5)+6

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Solution for 23-5k=2(2k-5)+6 equation: 



23-5k=2(2k-5)+6

We move all terms to the left:

23-5k-(2(2k-5)+6)=0



We calculate terms in parentheses: -(2(2k-5)+6), so:

2(2k-5)+6

We multiply parentheses

4k-10+6

We add all the numbers together, and all the variables

4k-4

Back to the equation:

-(4k-4)



We get rid of parentheses

-5k-4k+4+23=0

We add all the numbers together, and all the variables

-9k+27=0

We move all terms containing k to the left, all other terms to the right

-9k=-27

k=-27/-9

k=+3

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