a-8-2a+6=6(9+9)+7(10-10a)

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Solution for a-8-2a+6=6(9+9)+7(10-10a) equation: 



a-8-2a+6=6(9+9)+7(10-10a)

We move all terms to the left:

a-8-2a+6-(6(9+9)+7(10-10a))=0

We add all the numbers together, and all the variables

a-2a-(618+7(-10a+10))-8+6=0

We add all the numbers together, and all the variables

-1a-(618+7(-10a+10))-2=0



We calculate terms in parentheses: -(618+7(-10a+10)), so:

618+7(-10a+10)

determiningTheFunctionDomain
7(-10a+10)+618

We multiply parentheses

-70a+70+618

We add all the numbers together, and all the variables

-70a+688

Back to the equation:

-(-70a+688)



We get rid of parentheses

-1a+70a-688-2=0

We add all the numbers together, and all the variables

69a-690=0

We move all terms containing a to the left, all other terms to the right

69a=690

a=690/69

a=10

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