23+4b=2(b+4)+5

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Solution for 23+4b=2(b+4)+5 equation: 



23+4b=2(b+4)+5

We move all terms to the left:

23+4b-(2(b+4)+5)=0



We calculate terms in parentheses: -(2(b+4)+5), so:

2(b+4)+5

We multiply parentheses

2b+8+5

We add all the numbers together, and all the variables

2b+13

Back to the equation:

-(2b+13)



We get rid of parentheses

4b-2b-13+23=0

We add all the numbers together, and all the variables

2b+10=0

We move all terms containing b to the left, all other terms to the right

2b=-10

b=-10/2

b=-5

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