1/2(4x+2)-6=4(x-5)

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Solution for 1/2(4x+2)-6=4(x-5) equation: 



1/2(4x+2)-6=4(x-5)

We move all terms to the left:

1/2(4x+2)-6-(4(x-5))=0



Domain of the equation: 2(4x+2)!=0

x∈R



We multiply all the terms by the denominator


-((4(x-5)))*2(4x+2)-6*2(4x+2)+1=0



We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2



Wy multiply elements

-((4(x-5)))*2(4x+2)-12x(4+1=0



We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





We calculate terms in parentheses: -((4(x-5)))*2(4x+2), so:

(4(x-5)))*2(4x+2





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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