22=60/y+2

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Solution for 22=60/y+2 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

22 = 60/y+2 // - 60/y+2

22-(60/y)-2 = 0

22-60*y^-1-2 = 0

-60*y^-1 = -20 // : -60

y^-1 = 1/3

-1 < 0

1/(y^1) = 1/3 // * y^1

1 = 1/3*y^1 // : 1/3

3 = y^1

y = 3

y = 3

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