6/x-2=-6/x+7+6/(x-2)(x+7)

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Solution for 6/x-2=-6/x+7+6/(x-2)(x+7) equation:


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

6/x-2 = (6/(x-2))*(x+7)-6/x+7 // - (6/(x-2))*(x+7)-6/x+7

6/x-((6/(x-2))*(x+7))-(-6/x)-7-2 = 0

6/x-6*(x-2)^-1*(x+7)+6*x^-1-7-2 = 0

(-6*(x+7))/(x-2)+6/x+6/x-7-2 = 0

(-6*x*(x+7))/(x*(x-2))+(6*(x-2))/(x*(x-2))+(6*(x-2))/(x*(x-2))+(-7*x*(x-2))/(x*(x-2))+(-2*x*(x-2))/(x*(x-2)) = 0

6*(x-2)-6*x*(x+7)+6*(x-2)-7*x*(x-2)-2*x*(x-2) = 0

6*x-6*x^2-7*x^2-2*x^2-36*x+14*x+4*x-12-12 = 0

14*x-6*x^2-7*x^2-2*x^2-30*x+4*x-24 = 0

4*x-13*x^2-2*x^2-16*x-24 = 0

-15*x^2-12*x-24 = 0

-15*x^2-12*x-24 = 0

-3*(5*x^2+4*x+8) = 0

5*x^2+4*x+8 = 0

DELTA = 4^2-(4*5*8)

DELTA = -144

DELTA < 0

-3 = 0

-3/(x*(x-2)) = 0

-3/(x*(x-2)) = 0 // * x*(x-2)

-3 = 0

x belongs to the empty set

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