22=125-b/2

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Solution for 22=125-b/2 equation: 



22=125-b/2

We move all terms to the left:

22-(125-b/2)=0

We add all the numbers together, and all the variables

-(-b/2+125)+22=0

We get rid of parentheses

b/2-125+22=0

We multiply all the terms by the denominator


b-125*2+22*2=0

We add all the numbers together, and all the variables

b-206=0

We move all terms containing b to the left, all other terms to the right

b=206

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