5(z-4)=-2(3-2)

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Solution for 5(z-4)=-2(3-2) equation: 



5(z-4)=-2(3-2)

We move all terms to the left:

5(z-4)-(-2(3-2))=0

We add all the numbers together, and all the variables

5(z-4)-(-21)=0

We add all the numbers together, and all the variables

5(z-4)+21=0

We multiply parentheses

5z-20+21=0

We add all the numbers together, and all the variables

5z+1=0

We move all terms containing z to the left, all other terms to the right

5z=-1

z=-1/5

z=-1/5

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