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225x^2=3.6x
We move all terms to the left:
225x^2-(3.6x)=0
We add all the numbers together, and all the variables
225x^2-(+3.6x)=0
We get rid of parentheses
225x^2-3.6x=0
a = 225; b = -3.6; c = 0;
Δ = b2-4ac
Δ = -3.62-4·225·0
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.6)-\sqrt{12.96}}{2*225}=\frac{3.6-\sqrt{12.96}}{450} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.6)+\sqrt{12.96}}{2*225}=\frac{3.6+\sqrt{12.96}}{450} $
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